Name two 2-digit factors whose product is greater than 200 but less than 600
well, 200=20*10, so how about
20*11
Name 2 digit factors whose product is greater than 200 but less than 600
Well 200eqauls 20*10
So possibly
20*11
You have to watch out for extra factors of 10, which add zeroes to the product.
40 x 50 =2,000
300 and 500 that is my answer because I had this problem in my math book and I got it correct.
I think it is 300
200<600
200 is greater and 600 is less
To find two 2-digit factors whose product is greater than 200 but less than 600, we need to find pairs of numbers where both numbers are between 10 and 99.
Let's start by finding the smallest possible factor. The smallest 2-digit number is 10. To find the largest possible factor, we need to find the largest 2-digit number that, when multiplied by 10, gives us a product less than 600.
To calculate this, we divide 600 by 10: 600 ÷ 10 = 60. Since 60 is a 2-digit number, we can take it as the largest factor.
Now, we have the range of our potential factors: from 10 to 60. We can generate all possible pairs of 2-digit factors within this range and check their product to see if it meets the condition.
Starting with 10, we multiply it by each number in the range:
10 × 10 = 100
10 × 11 = 110
10 × 12 = 120
...and so on.
Continuing this process, we eventually find a pair where the product is greater than 200 but less than 600.
Let's go through the calculations:
10 × 21 = 210
10 × 22 = 220
...
10 × 26 = 260
The pair that satisfies the condition is 10 and 26, with a product of 260.
Therefore, one pair of 2-digit factors whose product is greater than 200 but less than 600 is 10 and 26.