Two aqueous solutions, both at 25.00°C (100.0 mL of 0.223 M
Pb(NO3)2 and 100.0 mL of 0.144 M Na2S), are mixed together in a
calorimeter with a Ccalorimeter of 11.8 J/°C. The temperature of the
solution increases by 2.40°C. Assuming that the density and
heat capacity of the solutions are the same as water, determine
the heat of reaction shown below.
Pb2+(aq) + S2-(aq) = PbS(s)
�H = ? kJ
q = mass H2O x specific heat H2O x (Tfinal- Tinitial) = ?
That gives you q = delta H for 0.0144 mols PbS formed.