a 450 cm^3 of aluminum (D = 2.7 g/cm^3) is lowered carefully into a completely full beaker of water? what is the weight of the water, in newtons, that spills out of the beaker?
Wt. = 450cm^3 * 0.998g/cm^3 = 449.1 g. =
0.449 kg of water displaced.
M*g = 0.449kg * 9.8N/kg = 4.40 N.