A coin jar contains 3 pennies, 8 nickels, 6 dimes, and 5 quarters. If a coin is chosen at random, what is the probability of choosing a dime?
a) 8/11
b) 3/8
c) 3/22
d) 3/11
So I'm confused. I solved this, but my answer was 6/22 --> 3/12 --> 1/4 (this being my simplified answer). How do I solve this?
6/22 --> 3/11
You did your simplifying wrong
idont get this either i got 200.8 as my answer
To solve this problem, you need to determine the total number of coins in the jar, as well as the number of dimes in the jar. Then you can find the probability of choosing a dime by dividing the number of dimes by the total number of coins.
To begin, you correctly identified that there are 3 pennies, 8 nickels, 6 dimes, and 5 quarters. To find the total number of coins, you add up the number of each type of coin:
Total number of coins = 3 + 8 + 6 + 5 = 22
Now, to find the probability of choosing a dime, you need to find the number of dimes (which is 6) and divide it by the total number of coins in the jar (which is 22):
Probability of choosing a dime = Number of dimes / Total number of coins
= 6 / 22
= 3 / 11
So the correct answer is (d) 3/11, which means the probability of choosing a dime is 3 out of 11.