is this the answer to B )
CH3CH2OH + 3O2 → 2CO2 + 3H2O
In winemaking, the sugars in grapes undergo fermentation by yeast to yield CH3CH2OH and CO2. During cellular respiration, sugar and ethanol are "burned" to water vapor andCO2.
Write a combustion reaction for ethanol. INCLUDE PHYSICAL STATES
I need help with balancing the equation
i think it's
CH3CH2OH + 3O2 → 2CO2 + 3H2O
then it said HINT:
Start by writing a balanced chemical equation for the fermentation reaction of C6H12O6 and for the respiration reaction (combustion) of C6H12O6...what formula should be used to find the standard enthalpy of a reaction? Use the standard enthalpy of formation values from your textbook when calculating the standard enthalpy of reaction for both fermentation and respiration. thanks!•
To write a balanced combustion reaction equation for ethanol (CH3CH2OH), you are on the right track. The balanced equation is:
2C2H5OH + 6O2 → 4CO2 + 6H2O
For balancing this equation, you need to make sure that the number of atoms of each element is the same on both sides of the equation. Here's how you can balance it step by step:
1. Start with the carbon (C) atoms. On the left side, you have 2 carbon atoms from the ethanol, and on the right side, you have 4 carbon atoms from the carbon dioxide (CO2). To balance the carbons, multiply the coefficient of CO2 by 2, giving you:
2C2H5OH + 6O2 → 8CO2 + 6H2O
2. Next, balance the hydrogen (H) atoms. On the left side, you have 6 hydrogen atoms from the ethanol, and on the right side, you have 12 hydrogen atoms from the water (H2O). To balance the hydrogens, multiply the coefficient of H2O by 2, giving you:
2C2H5OH + 6O2 → 8CO2 + 12H2O
3. Now, balance the oxygen (O) atoms. On the left side, you have 6 oxygen atoms from the ethanol and 12 oxygen atoms from the oxygen gas (O2), for a total of 18 oxygen atoms. On the right side, you have 32 oxygen atoms from the carbon dioxide and 24 oxygen atoms from the water, for a total of 56 oxygen atoms. To balance the oxygens, you need to multiply the coefficient of O2 by 4, giving you:
2C2H5OH + 12O2 → 8CO2 + 12H2O
Now, the equation is balanced with the same number of atoms on both sides.
Regarding the hint you mentioned, to find the standard enthalpy of a reaction, you can use the formula:
ΔH°rxn = ∑(ΔH°f products) - ∑(ΔH°f reactants)
This formula calculates the standard enthalpy of a reaction (ΔH°rxn) by subtracting the sum of the standard enthalpy of formation values of the reactants (∑(ΔH°f reactants)) from the sum of the standard enthalpy of formation values of the products (∑(ΔH°f products)). The standard enthalpy of formation values can be found in your textbook or other reference materials.
I hope this explanation helps! Let me know if you have any further questions.