joe is building a wooden cylindrical storage box. the box will have a volume og 6pi m^3. for design purposes, the thick wood for the top and the bottom costs \$6/m^2 and the thinner wood for the sides cost \$5/m^2.

a)express the cost of the wood as a function of the radius. make sure to simplify the expression.

b) if hoe can afford to spend at most \$72pi (~ \$226.19) to make the storage box, what are the dimensions of the box?

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1. cost=6*2PIr^2+5*2PIr*h

volume=PIr^2*h or h=volume/PIr^2
cost=12PIr^2+20PIr*6PI/PIr^2

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2. can you please explain how you got these equations?

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posted by samm
3. this is what i got:
cost=6*2PIr^2+5*2PIr*h
= 12PIr^2 + 10PIr*h
= 12PIr^2 + 10PIr*(6/r^2)
= 12PIr^2 + (60PI)/r

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posted by samm

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