A 4.30g sample of solid BaCl2 2H2O was heated such that the water turned to steam and was driven off.Assuming ideal behavior, what volume would that steam occupy at 1.00atm and 373K?

4.73L of gas is collected at 32 C and 625 mmHg. when the temperature is changed to standard, what is the new pressure?

To determine the volume occupied by the steam, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to calculate the number of moles of steam produced. We can do this by using the molar mass of water (H2O). The molar mass of H2O is 18.015 g/mol.

Given that the sample of BaCl2 2H2O is 4.30 g, we need to convert this mass to moles by dividing it by the molar mass:

Number of moles of BaCl2 2H2O = (mass of sample) / (molar mass of BaCl2 2H2O)
Number of moles of BaCl2 2H2O = 4.30 g / (molar mass of BaCl2 2H2O)

The molar mass of BaCl2 2H2O can be calculated by adding the molar masses of each element: Ba (137.33 g/mol), Cl (35.45 g/mol), H (1.01 g/mol), and O (16.00 g/mol). Therefore, the molar mass of BaCl2 2H2O is 244.26 g/mol.

Number of moles of BaCl2 2H2O = 4.30 g / 244.26 g/mol

Now we know the number of moles of water present in the sample. Since each mole of BaCl2 2H2O contains 2 moles of water (H2O), we can multiply the number of moles of BaCl2 2H2O by 2 to get the number of moles of water:

Number of moles of water = (Number of moles of BaCl2 2H2O) x 2

Next, we can use the ideal gas law equation to calculate the volume of the steam. Rearranging the equation, we get:

V = (nRT) / P

Given that the pressure is 1.00 atm and the temperature is 373 K, we can substitute these values into the equation:

V = (Number of moles of water) x (R) x (Temperature) / (Pressure)

Finally, substitute the values into the equation and calculate the volume:

V = (Number of moles of water) x (0.0821 L⋅atm/mol⋅K) x (373 K) / (1.00 atm)

By following these steps and performing the calculations, you should obtain the volume occupied by the steam produced from the 4.30g sample of solid BaCl2 2H2O at 1.00 atm and 373 K.