Two identical charges, each -8.00 x 10-5 C, are separated by a distance of 25.0 cm. Find the electric force between them?

To find the electric force between two charges, you can use Coulomb's Law, which states that the electric force (F) between two charges (q1 and q2) separated by a distance (r) is given by the equation:

F = (k * |q1 * q2|) / r^2

where:
- F is the electric force in newtons (N)
- k is Coulomb's constant, approximately equal to 9 x 10^9 Nm^2/C^2
- q1 and q2 are the magnitudes of the charges in coulombs (C)
- r is the distance between the charges in meters (m)

In this case, the charges are identical and have a magnitude of -8.00 x 10^-5 C each, and they are separated by a distance of 25.0 cm, which is equivalent to 0.25 m.

So, substituting the values into the formula:

F = (9 x 10^9 Nm^2/C^2) * |(-8.00 x 10^-5 C) * (-8.00 x 10^-5 C)| / (0.25 m)^2

Simplifying:

F = (9 x 10^9 Nm^2/C^2) * (8.00 x 10^-5 C)^2 / (0.25 m)^2

F = (9 x 10^9 Nm^2/C^2) * (64 x 10^-10 C^2) / (0.0625 m^2)

F = (9 x 64 x 10^-1 Nm^2) / (0.0625 C^2)

F = 576 x 10^-1 Nm^2 / 0.0625 C^2

Finally, calculating:

F = 9216 Nm^2 / C^2

Therefore, the electric force between the two charges is 9216 N.