What volume of 0.182 M Na3PO4 solution is necessary to completely react with 95.1 mL of 0.117 M CuCl2?
2Na3PO4 + 3CuCl2 ==> Cu3(PO4)2 + 6NaCl
mols CuCl2 = M x L = ?
Using the coefficients in the balanced equation, convert mols CuCl2 to mols Na3PO4.
Then M Na3PO4 = mols/L. You know mols and M, solve for L Na3PO4.
Na(Co3) = stuff
To find the volume of 0.182 M Na3PO4 solution necessary to completely react with 95.1 mL of 0.117 M CuCl2, we need to determine the stoichiometry of the reaction between Na3PO4 and CuCl2.
The balanced chemical equation for the reaction is:
3Na3PO4 + 2CuCl2 → Cu3(PO4)2 + 6NaCl
From the balanced equation, we can see that 3 moles of Na3PO4 react with 2 moles of CuCl2.
First, let's calculate the number of moles of CuCl2 using its concentration and volume:
moles of CuCl2 = concentration × volume
moles of CuCl2 = 0.117 M × 95.1 mL
Note: It's important to convert mL to liters by dividing by 1000 to maintain consistent units.
moles of CuCl2 = 0.117 M × 0.0951 L
moles of CuCl2 = 0.0111347 mol
According to the stoichiometry of the reaction, 3 moles of Na3PO4 react with 2 moles of CuCl2. Therefore, we need to find the moles of Na3PO4 required to react with the given moles of CuCl2.
moles of Na3PO4 = (moles of CuCl2 × 3) ÷ 2
moles of Na3PO4 = (0.0111347 mol × 3) ÷ 2
moles of Na3PO4 = 0.01670205 mol
Now we can find the volume of 0.182 M Na3PO4 solution needed to provide the calculated moles of Na3PO4, using the formula:
volume of Na3PO4 solution = moles ÷ concentration
volume of Na3PO4 solution = 0.01670205 mol ÷ 0.182 M
volume of Na3PO4 solution = 0.09168 L
Finally, convert the volume from liters to milliliters:
volume of Na3PO4 solution = 0.09168 L × 1000
volume of Na3PO4 solution = 91.68 mL
Therefore, it would require approximately 91.68 mL of 0.182 M Na3PO4 solution to completely react with 95.1 mL of 0.117 M CuCl2.