Find the integral of §x^1/2.e^xdx
at upper limit of 1/2 and lower limit of zero..show work plz
It appears you want
∫[0,1/2] √x e^x dx
if you let
x = u^2
dx = 2u du
then you have
∫[0,1/√2] u e^(u^2) * 2u du
= 2∫[0,1/√2] u^2 e^(u^2) du
Hmmm. Not much better. These involve the err function, so unless you have a table of that handy, you're stuck.