How many moles of aluminum ions are present in 0.80 mole of Al2(SO4)3
0.80 of course. Now, if you want the mass, that is 0.8 * (molar mass of compound)
Add up all the atomic masses involved in the molecule to get the molar mass.
To determine the number of moles of aluminum ions (Al3+) present in 0.80 moles of Al2(SO4)3, you need to understand the stoichiometry of the compound.
The compound Al2(SO4)3 can be broken down into its constituent ions:
Al2(SO4)3 → 2 Al3+ + 3 SO42-
From the balanced chemical equation, you can see that for every 1 mole of Al2(SO4)3, you have 2 moles of Al3+ ions.
Therefore, to find the number of moles of aluminum ions, you can perform the following calculation:
Number of moles of Al3+ ions = Number of moles of Al2(SO4)3 × (2 Al3+ / 1 Al2(SO4)3)
Plugging in the given value:
Number of moles of Al3+ ions = 0.80 moles × (2 Al3+ / 1 Al2(SO4)3)
Simplifying the equation:
Number of moles of Al3+ ions = 0.80 moles × 2
Number of moles of Al3+ ions = 1.60 moles
Therefore, there are 1.60 moles of aluminum ions present in 0.80 moles of Al2(SO4)3.