Imagine that you have a 7.00 gas tank and a 3.00 gas tank. You need to fill one tank with oxygen and the other with acetylene to use in conjunction with your welding torch. If you fill the larger tank with oxygen to a pressure of 145 , to what pressure should you fill the acetylene tank to ensure that you run out of each gas at the same time?

Is the answer 62.1 atm

I ran through the calculations and didn't get 62.1 atm. Show your work and I'll check our calculations.

To determine the pressure at which you should fill the acetylene tank, you can use the concept of Boyle's Law. Boyle's Law states that the pressure of a gas is inversely proportional to its volume at constant temperature.

Since you want both tanks to run out of gas at the same time, you can assume that the initial volume of both tanks is the same. Let's assign the volume of each tank as V.

According to Boyle's Law, P1 * V1 = P2 * V2, where P1 and P2 are the initial and final pressures, and V1 and V2 are the initial and final volumes.

Initially, the pressure of the oxygen tank (P1) is 145 atm, and the volume of both tanks (V1) is V.

When the oxygen tank runs out of gas, the remaining volume is V/2, and the pressure in the acetylene tank will be the final pressure (P2) at which you need to fill it.

So, using Boyle's Law, we can set up the following equation:

145 * V = P2 * (V/2)

Simplifying the equation:

290 * V = P2 * V

Dividing both sides by V:

290 = P2

Therefore, the pressure at which you should fill the acetylene tank is approximately 290 atm, not 62.1 atm.