Write the following into a balanced equation.
a) When a mixture of copper (II) oxide and carbon is heated, elemental copper forms and carbon monoxide evolves into the atmosphere.
b) When a concentrated solution of sodium hydroxide is added to an aqueous solution of lead acetate, lead hydroxide forms as a solid dispersed in a solution of sodium acetate
c) When aqueous solutions of cupric chloride and sodium phosphate are mixed, solid cupric phosphate separates from a solution of sodium chloride.
d) When heated in an aqueous solution of ammonium acetate, calcium oxide reacts to form calcium acetate, ammonia, and water
a) CuO(s) + C(s) => Cu(s) + CO(g)
b) 2 NaOH (conc) + Pb(CH3COO)2(aq) = Pb(OH)2(s) + 2 C2H3NaO2(l)
d)2 NH4C2H3O2 + CaO => C4H6CaO4 + 2 NH3 + H2O
a) The first step is to identify the elements and compounds involved in the reaction. In this case, we have copper (II) oxide (CuO), carbon (C), elemental copper (Cu), and carbon monoxide (CO).
Next, we need to balance the number of atoms on both sides of the equation. Start with the most complicated molecules or compounds and work your way to simpler ones.
1. Start by balancing the carbon atoms:
CuO + C -> Cu + CO
2. Next, balance the oxygen atoms:
CuO + C -> Cu + CO2
3. Finally, balance the copper atoms:
CuO + C -> 2Cu + CO2
Therefore, the balanced equation is:
CuO + C -> 2Cu + CO2
b) The reactants in this equation are sodium hydroxide (NaOH) and lead acetate (Pb(CH3COO)2), while the products are lead hydroxide (Pb(OH)2) and sodium acetate (NaCH3COO).
Here's how to balance this equation:
1. Balance the sodium atoms:
2NaOH + Pb(CH3COO)2 -> Pb(OH)2 + 2NaCH3COO
2. Balance the carbon, hydrogen, and oxygen atoms:
2NaOH + Pb(CH3COO)2 -> Pb(OH)2 + 2NaCH3COO
c) The reactants in this equation are cupric chloride (CuCl2) and sodium phosphate (Na3PO4), while the products are cupric phosphate (Cu3(PO4)2) and sodium chloride (NaCl).
Here's how to balance this equation:
1. Balance the copper atoms:
3CuCl2 + 2Na3PO4 -> Cu3(PO4)2 + 6NaCl
2. Balance the chlorine atoms:
3CuCl2 + 2Na3PO4 -> Cu3(PO4)2 + 6NaCl
3. Balance the sodium atoms:
3CuCl2 + 2Na3PO4 -> Cu3(PO4)2 + 6NaCl
Therefore, the balanced equation is:
3CuCl2 + 2Na3PO4 -> Cu3(PO4)2 + 6NaCl
d) The reactants in this equation are calcium oxide (CaO) and ammonium acetate (NH4CH3COO), while the products are calcium acetate (Ca(CH3COO)2), ammonia (NH3), and water (H2O).
Here's how to balance this equation:
1. Balance the calcium atoms:
CaO + (NH4)2CO3 -> CaCO3 + H2O + 2NH3
2. Balance the carbon, hydrogen, and oxygen atoms:
CaO + (NH4)2CO3 -> CaCO3 + H2O + 2NH3
3. Balance the nitrogen atoms:
CaO + (NH4)2CO3 -> CaCO3 + H2O + 2NH3
Therefore, the balanced equation is:
CaO + (NH4)2CO3 -> CaCO3 + H2O + 2NH3
a. 2 CuO + C2 --> 2 Cu + 2 CO
b. 2 NaOH + Pb(C2H3O2)2 --> Pb(OH)2 + 2 Na(C2H3O2)