Find the area of the region between the graphs of f(x)=3x+8 and
g(x)=x^2 + 2x+2 over [0,2].
I got 34/3.
∫[0,2] (x^2+2x+2) dx
= 1/3 x^3 + x^2 + 2x [0,2]
= 8/3 + 4 + 4
= 32/3
It would be nice for you to show your work...
g(x)=x^2 + 2x+2 over [0,2].
I got 34/3.
= 1/3 x^3 + x^2 + 2x [0,2]
= 8/3 + 4 + 4
= 32/3
It would be nice for you to show your work...