# Calculus

Find the area of the region between the graphs of f(x)=3x+8 and
g(x)=x^2 + 2x+2 over [0,2].

I got 34/3.

1. 0
2. 0
3. 3
1. ∫[0,2] (x^2+2x+2) dx
= 1/3 x^3 + x^2 + 2x [0,2]
= 8/3 + 4 + 4
= 32/3

It would be nice for you to show your work...

1. 0
2. 0
posted by Steve

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