The refractive indices of materials A and B have a ratio of nA/nB = 1.68. The speed of light in material A is 1.26 x 108 m/s. What is the speed of light in material B
thankyou could you help me with what formula you used plz
To find the speed of light in material B, we can use the relationship between the speed of light and the refractive index.
The refractive index (n) of a material is defined as the ratio of the speed of light in a vacuum (c) to the speed of light in that material (v). Mathematically, it is expressed as:
n = c / v
We are given the ratio of refractive indices of materials A and B as nA/nB = 1.68. This implies that the refractive index of material A (nA) divided by the refractive index of material B (nB) is equal to 1.68.
So, we can write the equation as:
nA / nB = 1.68
From the given information, we know the speed of light in material A (vA) is 1.26 x 10^8 m/s. We need to find the speed of light in material B (vB).
We can rewrite the refractive index equation for both materials:
nA = c / vA
nB = c / vB
Dividing the two equations, we get:
nA / nB = (c / vA) / (c / vB)
1.68 = vB / vA
Now, rearrange the equation to solve for vB:
vB = 1.68 * vA
Substituting the known value for vA:
vB = 1.68 * (1.26 x 10^8 m/s)
Calculating the value:
vB = 2.1168 x 10^8 m/s
Therefore, the speed of light in material B is approximately 2.1168 x 10^8 m/s.