if a photon of light has an energy of 2.35x10^-19 J, calculate the frequency and wave length. What solution do I use to get the answer?

E = hc/wavlength

Solve for wavelength

Then c = freq x wavelength for freq.

To calculate the frequency and wavelength of a photon of light, you can use the equation:

c = λν

where:
c = speed of light in a vacuum (approximately 3.00 x 10^8 m/s)
λ = wavelength of the photon
ν = frequency of the photon

To find the frequency (ν), you can rearrange the equation to:

ν = c / λ

To find the wavelength (λ), you can rearrange the equation to:

λ = c / ν

Now, let's use the given energy of the photon (2.35 x 10^-19 J) and the equation E = hν, where:
E = energy of the photon
h = Planck's constant (approximately 6.626 x 10^-34 J·s)

By rearranging the equation, we can solve for the frequency (ν):

ν = E / h

Substituting the given energy value, we have:

ν = (2.35 x 10^-19 J) / (6.626 x 10^-34 J·s)

Now, calculate the value of ν using a scientific calculator or a calculator that supports scientific notation. The answer will give you the frequency of the photon.

Next, to find the wavelength, substitute the calculated frequency (ν) into the equation:

λ = c / ν

Again, calculate the value using the speed of light (c) and the frequency (ν). This will give you the wavelength of the photon.

In both cases, make sure to match the units (if necessary) to ensure a consistent result.

You can use the given energy of the photon and solve step by step using the above equations to calculate the frequency and wavelength of the photon.