A 100 grams of bullet is fired from a 10 kg with a speed of 1000 m/s. What is the speed of the recoil of the gun?
.1 * 1000 = 10 v
v = 10
10m/s
To find the speed of the recoil of the gun, we can use the principle of conservation of momentum.
Conservation of momentum states that the total momentum of an isolated system remains constant if no external forces act on it. In this case, the gun and the bullet can be considered as an isolated system.
The momentum of an object is defined as the product of its mass and velocity:
Momentum = mass × velocity
Let's denote the mass of the bullet as m1 (100 grams = 0.1 kg) and the mass of the gun as m2 (10 kg). The initial velocity of the bullet is v1 (1000 m/s), and we need to find the recoil velocity of the gun, which we can denote as v2.
According to conservation of momentum, the total initial momentum of the system is equal to the total final momentum:
(mass of bullet × initial velocity of bullet) + (mass of gun × initial velocity of gun) = (mass of bullet × final velocity of bullet) + (mass of gun × final velocity of gun)
(0.1 kg × 1000 m/s) + (10 kg × 0 m/s) = (0.1 kg × final velocity of bullet) + (10 kg × final velocity of gun)
Since the bullet is fired, its final velocity will be zero:
(0.1 kg × 1000 m/s) + (10 kg × 0 m/s) = (0.1 kg × 0 m/s) + (10 kg × final velocity of gun)
100 kg⋅m/s = 10 kg × final velocity of gun
Now, we can solve for the final velocity of the gun:
final velocity of gun = (100 kg⋅m/s) / 10 kg
final velocity of gun = 10 m/s
Therefore, the speed of the recoil of the gun is 10 m/s.