Explain how you can use Boyle's law to determine the new volume of a gas when it's pressure is increased from 270 kPa to 540 kPa? The original volume of gas was 1 l. Assume the temperature and number of particles are consistent. What is the new volume?

Did this yesterday. With 270 kPa being half of 540 kPa I got an answer of two and the teacher marked it correct

Huh?

You SQUEEZED the gas

P1V1 = P2 V2
V2 = (P1/P2) V1
1/2 not two

Thanks guys

You are welcome.

Boyle's Law states that the pressure and volume of a given amount of gas are inversely proportional, at a constant temperature and number of particles. In other words, as the pressure on a gas increases, its volume decreases, and vice versa.

To determine the new volume of the gas, we can use the formula for Boyle's Law:

P₁V₁ = P₂V₂

Where P₁ and V₁ represent the initial pressure and volume, and P₂ and V₂ represent the new pressure and volume.

Given:
P₁ = 270 kPa
V₁ = 1 L
P₂ = 540 kPa

We need to solve for V₂.

Now, let's plug in the values into the equation:

270 kPa * 1 L = 540 kPa * V₂

To solve for V₂, we need to isolate it. Divide both sides of the equation by 540 kPa:

V₂ = (270 kPa * 1 L) / 540 kPa

Simplifying the equation:

V₂ = 0.5 L

Therefore, the new volume of the gas, when the pressure is increased from 270 kPa to 540 kPa, is 0.5 L.