This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the triangle is 15.7 centimeters. The equation 2a + b = 15.7 can be used to find the side lengths.

If one of the longer sides is 6.3 centimeters, what is the length of the base?

well, just plug in 6.3 for a:

2(6.3)+b = 15.7

Now just solve for b.

i need help

To find the length of the base in an isosceles triangle, you can use the equation given: 2a + b = 15.7, where 'a' represents the length of the equal sides and 'b' represents the length of the base.

In this case, you are given that one of the longer sides is 6.3 centimeters. Let's substitute this value into the equation and solve for 'b':

2(6.3) + b = 15.7

Simplifying the equation:

12.6 + b = 15.7

Now, isolate 'b' by subtracting 12.6 from both sides:

b = 15.7 - 12.6

b = 3.1

Therefore, the length of the base is 3.1 centimeters.