A 400.0 kg mass experiences a horizontal push force of +720 N and a friction force of 320 N.
A) assuming the mass is initially moving at 5.0 m/s how far will it travel in 6.0s?
B) how much work does the 720.0 Newton force do over the distance determined in part (a)
C) calculate the power of the 720.0 N force using the results from part b and the given amount of time.
what do you think the answer is
i'm afraid i cant help you then
a = (F-Fk)/M = (720-320)/400 = 1.0 m/s^2
A. d = Vo*t + 0.5a*t^2.
Vo = 5 m/s.
t = 6 s.
d = ?.
B. Work = F*d.
C. Power = Work/t in J/s = Watts.
a) Fnet=ma
F-Ff=ma
720-320=400a
400=400a
a=1 m.s^-2
x=vt+0.5at^2
x=(5)(6)+0.5(1)(6)^2
x=48 m
b) W=Fxcos¤
=720*43*cos0
= 34560 J
c)P=W/t
=34560/6
=5760 W
HOPE THAT HELPS
Cheater!!!!!!!!!!!!!!!!!!!
A) To determine the distance traveled by the mass, we can use the equations of motion. The net force acting on the mass is the difference between the horizontal push force and the friction force:
Net Force = Push Force - Friction Force
= 720 N - 320 N
= 400 N
The acceleration of the mass can be calculated using Newton's second law:
Net Force = Mass * Acceleration
Rearranging the equation, we have:
Acceleration = Net Force / Mass
= 400 N / 400 kg
= 1 m/s²
Using the initial velocity (5.0 m/s), acceleration (1 m/s²), and time (6.0 s), we can find the distance by using the equation of motion:
Distance = Initial Velocity * Time + 1/2 * Acceleration * Time²
= (5.0 m/s) * (6.0 s) + 1/2 * (1 m/s²) * (6.0 s)²
= 30 m + 1/2 * 1 m/s² * 36 s²
= 30 m + 18 m
= 48 m
Therefore, the mass will travel a distance of 48 meters in 6.0 seconds.
B) The work done by a force is given by the equation:
Work = Force * Distance
In this case, the force is 720 N and the distance traveled is 48 m. Therefore:
Work = 720 N * 48 m
= 34,560 J
So the 720.0 Newton force does 34,560 Joules of work over the distance determined in part (a).
C) Power is the rate at which work is done, and it is calculated using the equation:
Power = Work / Time
From part (b), we found that the work done is 34,560 J. Given that the time is 6.0 seconds, we can calculate the power:
Power = 34,560 J / 6.0 s
= 5,760 W
Therefore, the power of the 720.0 N force is 5,760 Watts using the results from part (b) and the given amount of time.