A car is travelling at 60km/h when applies his brakes.If the car decelerates uniformly at 5.6m/s2,how far does the car go after the brakes are applied before coming to rest?

well, 60 km/hr = 16.67 m/s

v(t) = 16.67 - 5.6t
set v=0 and solve for t, then plug that into

s(t) = 16.67t - 2.8t^2

200

To find the distance the car travels after the brakes are applied before coming to rest, we can use the equation of motion:

v^2 = u^2 + 2as

Where:
v = final velocity (0 m/s because the car comes to rest)
u = initial velocity (60 km/h or 16.67 m/s)
a = acceleration (deceleration in this case, -5.6 m/s^2)
s = distance traveled

First, let's convert the initial velocity from km/h to m/s:
u = 60 km/h = 60 * (1000/3600) = 16.67 m/s

Now let's substitute the values into the equation:

0^2 = 16.67^2 + 2 * (-5.6) * s

Simplifying the equation:

0 = 277.5644 - 11.2s

Rearranging the equation to solve for s:

11.2s = 277.5644

s = 277.5644 / 11.2

s ≈ 24.80 meters

Therefore, the car travels approximately 24.80 meters after the brakes are applied before coming to rest.