a man leaves half of his property to his wife.one third to his son and the remaining to his daughter. if the daughter share is 40000. find how much money did he leave. how much did his wife get? what is his son share?
Total part of property = 10
Wife 1/5
Son 1/3
Thus, daughter= (10/10 )- (1/5+1/3)
= 10/10-8/10
= 2/10
2/10=40000, 10/2¡Á40000=
10¡Á20000=200000
19,000
To answer the question, let's break it down into steps:
Step 1: Understand the given information:
- The man left half of his property to his wife.
- He left one-third of his property to his son.
- His daughter's share is $40,000.
Step 2: Calculate the daughter's share:
Since the daughter's share is given as $40,000, this means it is equal to the remaining portion of the property after the wife and son receive their shares. Therefore, we can set up the equation:
Remaining portion = Daughter's share = $40,000
Step 3: Calculate the total property value:
If the daughter's share represents the remaining portion, we can calculate the total property value by multiplying it by the reciprocal of the share that the daughter received. In this case, the daughter received one-third, so:
Total property value = Daughter's share / (1/3)
Total property value = $40,000 / (1/3) = $120,000
Step 4: Calculate the wife's share:
The wife received half of the property, so her share is:
Wife's share = Total property value * (1/2)
Wife's share = $120,000 * (1/2) = $60,000
Step 5: Calculate the son's share:
The son received one-third of the property, so his share is:
Son's share = Total property value * (1/3)
Son's share = $120,000 * (1/3) = $40,000
Step 6: Answer the questions:
The man left a total of $120,000. His wife received $60,000, and his son received $40,000.
Therefore, the answers are:
- Total money left: $120,000
- Wife's share: $60,000
- Son's share: $40,000
clearly the daughter gets 1/6 of the total.
Total part of property = 10
Wife 1/5
Son 1/3
Thus, daughter= (10/10 )- (1/5+1/3)
= 10/10-8/10
= 2/10
2/10=40000, 1=20000,
10¡Á20000=200000