solve the differential equation that satisfies the given condition:
dy/dx=(ycos(x))/(6+y^2), y(0)=1
y' = (y cosx)/(6+y^2)
(6+y^2)/y dy = cosx dx
6lny + 1/2 y^2 = sinx + c
y^2 + 12lny = 2sinx + c
I don't see any way to express y explicitly as a function of x, using elementary functions.