Chemistry

NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.049 M in NH4Cl at 25 °C?

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  1. .........NH4^+ + H2O ==> H3O^+ + NH3
    I......0.049..............0.......0
    C........-x...............x.......x
    E.....0.049-x.............x.......x

    Ka for NH4^+ = (Kw/Kb for NH3) = (x)(x)/(0.049-x)
    Solve for x = (H3O^+) and convert to pH.

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