A lever is used to lift a heavy load. A 50 N force pushes one end of the lever down 1.2 m and the load
rises 0.2 m. Calculate in weight of the load. Neglect friction
300 N
To calculate the weight of the load, we can use the principle of moments, which states that the sum of the moments on one side of the lever must be equal to the sum of the moments on the other side.
The moment of a force is equal to the product of the force and its perpendicular distance from the pivot point. In this case, the pivot point is the point where the lever is being pushed down.
Let's denote the weight of the load as "W." We know that a force of 50 N is applied to one end of the lever, pushing it down by 1.2 m. The load rises by 0.2 m.
To find the weight of the load, we set up the equation:
Force x Distance = Weight x Distance
50 N x 1.2 m = W x 0.2 m
60 Nm = 0.2W
To solve for W, we divide both sides of the equation by 0.2:
W = (60 Nm) / (0.2 m)
W = 300 N
Therefore, the weight of the load is 300 N.
To calculate the weight of the load, we can use the principle of levers, which states that the product of the force and its distance from the pivot is equal on both sides of the lever.
In this case, we can consider the lever as having two arms - the effort arm and the load arm. The effort arm is the part of the lever where the 50 N force is applied, and the load arm is the part of the lever where the load is located.
Let's denote the length of the effort arm as D1 (1.2 m) and the length of the load arm as D2 (0.2 m). The force on the effort arm is 50 N.
According to the principle of levers, the product of the force and its distance from the pivot is the same on both sides of the lever. Therefore, we can write the equation as:
Force on the effort arm x distance on the effort arm = Weight of the load x distance on the load arm
50 N x 1.2 m = Weight of the load x 0.2 m
Now we can solve for the weight of the load:
Weight of the load = (50 N x 1.2 m) / 0.2 m
Weight of the load = 300 N
Therefore, the weight of the load is 300 N.