4. A 9.25 g sample of sodium reacts completely with sulfur to form a compound with a weight of 15.75 g.
I have no clue how to do this problem will some please explain it to me thank you
15.75g = mass Na + mass S
-9.25g = mass Na
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6.50 = mass S
mols Na = mass/atomic mass = ?
mols S = mass/atoic mass = ?
Now find the ratio of the two elemenes to each other with the smaller number being no less than 1.00. The esy way to do this is to divide the smaller number by itself, then divide the other number by the same small number. This will give you the empirical formula.
In this problem, you are given the weights of sodium and the compound formed when it reacts with sulfur. You are asked to find the weight of sulfur in the compound.
To solve this, we can use the concept of the Law of Conservation of Mass. According to this law, mass is neither created nor destroyed during a chemical reaction. Therefore, the total mass of the reactants should be equal to the total mass of the products.
Let's break it down step by step:
Step 1: Calculate the weight of sulfur in the compound.
To find the weight of sulfur in the compound, subtract the weight of sodium from the total weight of the compound:
Weight of sulfur = Total weight of the compound - Weight of sodium
Step 2: Plug in the given values.
Total weight of the compound = 15.75 g
Weight of sodium = 9.25 g
Substituting the given values into the equation from Step 1:
Weight of sulfur = 15.75 g - 9.25 g
Step 3: Perform the calculation.
Weight of sulfur = 6.50 g
Thus, the weight of sulfur in the compound is 6.50 grams.
Please note that the Law of Conservation of Mass is a fundamental concept in chemistry. By applying this law, you can solve various types of problems involving the calculation of reactants, products, and their weights.