A 0.179 g sample of a vitamin C tablet was titrated with 0.1000 M NaOH according to the procedure in this experiment. The titration required 7.08 mL of NaOH solution.
How many moles of NaOH were used in the titration?
How Many moles of Vitamin C were in the sample?
What was the mass percent of vitamin C in the sample?
I got 0.000708 mols of NaOH 0.000708 moles Vitamin C for part A and B.
You have an equation in that lab procedure. Use that equation (balanced).
mols NaOH = M x L = ?
mols vitamin C. Using the coefficients in the balanced equation, convert mols NaOH to mols vitamin C.
Then grams vitamin C = mols vitamin C x molar mass vitamin C = ?
mass% = (grams vitamin C/mass sample)*100 = ?
To find the number of moles of NaOH used in the titration, we can use the equation:
moles of NaOH = concentration of NaOH (in M) × volume of NaOH (in L)
Given:
Concentration of NaOH = 0.1000 M
Volume of NaOH = 7.08 mL = 0.00708 L
moles of NaOH = 0.1000 M × 0.00708 L = 0.000708 moles
So, you are correct. The number of moles of NaOH used in the titration is 0.000708 moles.
To find the number of moles of vitamin C in the sample, we need to use the stoichiometry of the balanced chemical equation between vitamin C and NaOH. However, you have not provided the balanced chemical equation, so I cannot provide the answer for this part. Please provide the balanced chemical equation, and I will be able to help you calculate the number of moles of vitamin C in the sample.
For the mass percent of vitamin C in the sample, we need to use the equation:
mass percent = (mass of vitamin C / mass of sample) × 100
Given:
Mass of vitamin C sample = 0.179 g
mass percent = (0.179 g / mass of sample) × 100
Since you haven't provided the mass of the sample, I cannot provide the exact mass percent. Please provide the mass of the sample, and I will be able to help you calculate the mass percent of vitamin C in the sample.
To find the number of moles of NaOH used in the titration, you can use the equation:
moles NaOH = concentration NaOH x volume NaOH
Given that the concentration of NaOH is 0.1000 M and the volume used is 7.08 mL (which can be converted to liters by dividing by 1000), you can calculate the number of moles of NaOH used in the titration:
moles NaOH = 0.1000 M x 7.08 mL / 1000 mL/L
moles NaOH = 0.000708 mol
So, you received the correct value for the moles of NaOH used in the titration, which is 0.000708 mol.
To find the number of moles of vitamin C in the sample, you need to keep in mind that vitamin C (ascorbic acid) reacts with NaOH in a 1:1 molar ratio. This means that the moles of vitamin C in the sample will be equal to the moles of NaOH used in the titration. Therefore, the number of moles of vitamin C in the sample is also 0.000708 mol.
For the mass percent of vitamin C in the sample, you need to use the formula:
mass percent = (mass of vitamin C / mass of sample) x 100%
To find the mass of vitamin C in the sample, you can use the molar mass of vitamin C, which is 176.12 g/mol. So:
mass of vitamin C = number of moles of vitamin C x molar mass of vitamin C
mass of vitamin C = 0.000708 mol x 176.12 g/mol
mass of vitamin C = 0.125 g
Given that the given sample of the vitamin C tablet weighs 0.179 g, you can now calculate the mass percent of vitamin C in the sample:
mass percent = (0.125 g / 0.179 g) x 100%
mass percent = 69.8%
So, the correct value for the mass percent of vitamin C in the sample is 69.8%.