What would be the equation for NaOH + H2SO4 be?
Would the porducts be H2O + NaHSo4 or
H2O + Na2SO4?
If it's the second one, which I think it is, where does that extra H go?
2NaOH+H2SO4>>>Na2SO4 +2 HOH *HOH is a good way to balance these, then rewrite it as H2O)
NaOH + H2SO4>>NaHSO4 + HOH which is a possible reaction also.
So both reactions are possible, and in fact it can be a mix of products such as this..
3NaOH + 2H2SO4>>>3HOH + NaHSO4 + Na2SO4
and to add confusion, the ratio of products does not have to be 1:1, it can be balanced many other ways.
http://www.markedbyteachers.com/gcse/science/produce-two-different-metal-salts-nahso4-and-na2so4-through-an-application-of-specific-stoichiometric-ratios-in-a-reaction-of-diprotic-sulfuric-acid-h2so4-with-sodium-hydroxide-naoh.html
To determine the equation and products for the reaction between NaOH (sodium hydroxide) and H2SO4 (sulfuric acid), you need to balance the equation correctly. Here's how you can do it:
1. Write the unbalanced equation:
NaOH + H2SO4 → ?
2. Determine the ions involved in each compound:
NaOH dissociates into Na+ and OH- ions.
H2SO4 dissociates into H+ and SO4^2- ions.
3. Balance the equation by ensuring the charges are equal on both sides. In this case, we want to neutralize the Na+ ion from NaOH with the H+ ion from H2SO4. The equation becomes:
2NaOH + H2SO4 → Na2SO4 + 2H2O
Thus, the correct equation is 2NaOH + H2SO4 → Na2SO4 + 2H2O.
Regarding your question about the extra H, it forms water (H2O) as a product when it combines with the OH- ion from NaOH. So, in the balanced equation, the extra H combines with the OH- to produce water (H2O), resulting in the products Na2SO4 and 2H2O.