A car travels 28 m [E 35° S] and then turns and travels 45 m [S]. the whole motion takes 6.9s.

what is average velocity?

answer: 9.5m/s [E 69° S]

How do i find the displacement to find V if its not a right triangle

Well, if it's not a right triangle, I guess you could try asking the triangle to kindly become a right triangle. Sometimes triangles are very accommodating like that. But let's assume it's not feeling so cooperative.

To find the displacement, you can use vector addition. Start by breaking down the given vectors into their x and y components. For the first vector, the x component would be 28 cos(35°) and the y component would be 28 sin(35°). For the second vector, since it's straight south, the x component would be 0 and the y component would be -45.

Now add up the x components and the y components separately. That will give you the total x displacement and y displacement. And voila, you have your displacement vector!

To find the average velocity, divide the displacement vector by the total time taken. Although I have to give you credit for the creativity, I don't think there are any funny jokes I can make about this process. It's all math and science, not clown business.

To find the displacement and average velocity when it's not a right triangle, you can use vector addition.

1. First, you need to find the x and y components of each vector separately.
- For the first vector, 28 m [E 35° S], the x-component is 28 * cos(35°) and the y-component is -28 * sin(35°).
- For the second vector, 45 m [S], the x-component is 0 (since it's purely in the y direction) and the y-component is -45.

2. Next, add up the x and y components separately to find the final x and y components.
- The final x-component is the sum of the x-components from both vectors.
- The final y-component is the sum of the y-components from both vectors.

3. Now, you can find the magnitude of the displacement using the Pythagorean theorem.
- The magnitude of the displacement is the square root of (final x-component^2 + final y-component^2).

4. Lastly, divide the magnitude of the displacement by the total time taken to get the average velocity.
- Average velocity = magnitude of displacement / total time.

By following these steps, you should be able to find the displacement and average velocity of the car's motion.

To find the average velocity, you need to find the displacement of the car. The average velocity is defined as the total displacement divided by the total time taken.

In this case, the car travels 28 m [E 35° S] and then turns and travels 45 m [S]. To find the displacement, we need to find the net distance and direction traveled by the car.

First, we break down the initial displacement vector of 28 m [E 35° S]. This means that the car has traveled 28 m in an easternly direction and then turned 35° south. To find the horizontal and vertical components of this vector, we can use trigonometry.

Horizontal Component = 28 m * cos(35°)
Vertical Component = 28 m * sin(35°)

Next, we consider the second displacement vector of 45 m [S]. This means that the car has traveled 45 m directly south.

To find the net displacement, we need to add the horizontal and vertical components obtained from the first displacement vector to the displacement of the second displacement vector.

Net Horizontal Displacement = Horizontal Component of the first vector + 0 (no horizontal displacement in the second vector)
Net Vertical Displacement = Vertical Component of the first vector + Displacement of the second vector

Now, you can use these components to find the magnitude and direction of the net displacement. The magnitude can be calculated using the Pythagorean theorem:

Magnitude = sqrt((Net Horizontal Displacement)^2 + (Net Vertical Displacement)^2)

The direction can be found using trigonometry again:

Direction = arctan(Net Vertical Displacement / Net Horizontal Displacement)

Finally, to find the average velocity, divide the displacement by the total time taken:

Average Velocity = Magnitude of the net displacement / Total time taken

By calculating the values, you will get an average velocity of 9.5 m/s [E 69° S].

D = 28m[325o]CCW + 45m[270o]CCW.

X = 28*Cos325 + 45*Cos270 = 22.9 + 0 = 22.9 m.
Y = 28*sin325 - 45*sin270 = -16.1 - 45 = -61.1 m.
Q4.

Tan A = Y/X = -61.1/22.9 = -2.66812.
A = -69.5o = [E69.5oS] = 290.5 CCW.

D = Y/sin A = -61.5/sin290.5 = 65.2 m.

V = D/T = 65.2m/6.9s = 9.5 m/s.[E69.5o]