the floor plan of a room has a scale of 2.5 in.:32ft. in the drawing,the length of the room is 8in.and the width of the room is 6 in. what is the perimeter of the actual room?
i think is 392 ft or help
2.5/32 = 8/x
2.5x = 256
x = 102.4 feet = length
2.5/32 = 6/x
2.5x = 192
x = 76.8 feet = width
P = 2L + 2W
P = (2 * 102.4) + (2 * 76.8)
P = 204.8 + 153.6
P = 358.4
Check my math.
To find the perimeter of the actual room, we need to convert the measurements from the drawing using the given scale.
Given:
Scale: 2.5 in. : 32 ft.
Length (in the drawing): 8 in.
Width (in the drawing): 6 in.
First, let's convert the length and width from the drawing to feet using the given scale.
To convert length:
8 in. * (32 ft. / 2.5 in.) = 102.4 ft.
To convert width:
6 in. * (32 ft. / 2.5 in.) = 76.8 ft.
Now that we have the actual length and width of the room in feet, we can calculate the perimeter using the formula:
Perimeter = 2 * (Length + Width)
Perimeter = 2 * (102.4 ft. + 76.8 ft.)
Perimeter = 2 * 179.2 ft.
Perimeter = 358.4 ft.
Therefore, the perimeter of the actual room is 358.4 ft.