A girl delivering newspapers travels 3 blocks west, 3 blocks north, then 6 blocks east.
What is the magnitude of her resultant displacement?
Answer in units of blocks.
d=3W+3N+6E
d=3W+3N-6W
d=3N+3E
magd=sqrt(3^2+3^2)
your teacher is far too easy.
To find the magnitude of the resultant displacement, we need to calculate the total distance covered in both the north and west directions.
Starting with the 3 blocks west, the girl moves in the west direction, so we can represent this as -3 units in the x-axis.
Next, the girl moves 3 blocks north, so we can represent this as +3 units in the y-axis.
After that, the girl moves 6 blocks east, so we can represent this as +6 units in the x-axis.
Now we can find the total displacement in both the x-axis and y-axis by summing up the distances traveled in each direction separately:
Displacement in the x-axis: -3 + 6 = 3 units
Displacement in the y-axis: 3 units
To find the magnitude of the resultant displacement, we can use the Pythagorean theorem:
Resultant Displacement = √(x^2 + y^2)
Plugging in our values:
Resultant Displacement = √(3^2 + 3^2)
Resultant Displacement = √(9 + 9)
Resultant Displacement = √18
Resultant Displacement ≈ 4.24 blocks (rounded to two decimal places)
Hence, the magnitude of her resultant displacement is approximately 4.24 blocks.