Please give the complete mechanism for the
acid catalyzed addition of methanol to 3 -
methylbutene
The acid-catalyzed addition of methanol to 3-methylbutene involves the following steps:
1. Protonation: The acid (such as sulfuric acid, H2SO4) donates a proton (H+) to the double bond carbon (C=C) in 3-methylbutene. This protonation makes the carbon more electrophilic and creates a positively charged intermediate.
2. Nucleophilic attack: Methanol (CH3OH) acts as a nucleophile and attacks the electrophilic carbon, forming a new bond between the carbon and oxygen in methanol. This reaction is known as nucleophilic addition.
3. Deprotonation: A water molecule (H2O) or other solvent molecule can now act as a base and deprotonate the positively charged intermediate, restoring its neutral charge.
Overall, the acid-catalyzed addition of methanol to 3-methylbutene results in the formation of a new molecule called 3-methylbutan-2-ol, with the methanol molecule added to the double bond carbon in 3-methylbutene.
To find more detailed mechanism diagrams, it is recommended to refer to organic chemistry textbooks or online resources that provide illustrations and explanations of specific reactions like this one.