A ball rolls down an incline with an acceleration of 10 cm/s^2. If it starts with an initial velocity of 0 cm/s and has a velocy of 50 cm/s when it reaches the bottom of the ramp, how long is the ramp?

To find the length of the ramp, we can use the following equation of motion:

v^2 = u^2 + 2as

Where:
v = final velocity
u = initial velocity
a = acceleration
s = distance or length

Given:
initial velocity (u) = 0 cm/s
acceleration (a) = 10 cm/s^2
final velocity (v) = 50 cm/s

Plugging the values into the equation, we get:

50^2 = 0^2 + 2 * 10 * s

2500 = 20s

Dividing both sides by 20:

s = 2500 / 20
s = 125 cm

Therefore, the length of the ramp is 125 cm.