The perimeter of a rectangle picture frame is 30 inches. The length of the frame is three less than twice the width. What are the dimensions of the frame?

I know that the perimeter is 30 in., the length is 2w-3, and the width is w, but I don't know what to do after that?

それで答えは何ですか

Thank you so much! I needed help and since it's the weekend i couldn't ask my teacher.

You are very welcome. :-)

24 doesn't equal 30 I'm confused

To find the dimensions of the frame, you can set up an equation using the given information. Let's denote the width of the frame as "w" inches and the length as "2w-3" inches.

The perimeter of a rectangle is given by the formula: P = 2(l + w), where P is the perimeter, l is the length, and w is the width.

Given that the perimeter is 30 inches, we can substitute these values into the formula:

30 = 2((2w-3) + w)

Now, simplify the equation by combining like terms:

30 = 2(3w - 3)

Next, distribute the 2 to each term inside the parentheses:

30 = 6w - 6

Now, isolate the variable by adding 6 to both sides of the equation:

30 + 6 = 6w

Combine like terms:

36 = 6w

Finally, divide both sides of the equation by 6 to solve for w:

w = 36/6 = 6

So, the width of the frame is 6 inches.

To find the length, substitute the value of w back into the expression for the length:

Length = 2w - 3 = 2(6) - 3 = 12 - 3 = 9

Therefore, the dimensions of the frame are: width = 6 inches and length = 9 inches.

You have a good start.

P = 2L + 2W

30 = 2(2w - 3) + 2W

30 = 6W - 6

24 = 6W

4 = W