A 45 kg girl is sitting on one end of a see-saw, 0.6 m away from the the pivot pt. How far away form the pivot pt must a 60 kg boy sit on the other side in order for the see saw o be balanced?
W1*d1 = W2*d2.
45*0.6 = 60*d2.
d2 = 0.45 m.
Ah, the classic see-saw problem. Let's see if we can get to the bottom of it.
So, we have a 45 kg girl on one end, 0.6 m away from the pivot point. And we need to find out where the 60 kg boy should sit to balance things out.
Now, in order for the see-saw to be balanced, we need to consider the lever arm and the torque. Torque is basically the rotational force, kind of like the see-saw's version of twerking.
To calculate the torque, we can use the formula: Torque = Force x Distance.
The torque on one side of the see-saw will be equal to the torque on the other side. So, for the girl's side, we have 45 kg x 0.6 m = 27 Nm.
Now, we need to find where the boy should sit to balance it out. Let's call that distance "x".
On the boy's side, the torque will be 60 kg x x. And we want this torque to be equal to 27 Nm.
So, we have 60 kg x x = 27 Nm. Solving for x, we get x = 27 Nm / 60 kg.
Doing the math, we find that x ≈ 0.45 m.
So, to balance the see-saw, the 60 kg boy should sit about 0.45 meters away from the pivot point. And voila! The see-saw will be as balanced as a tightrope walk on a unicycle.
To balance the see-saw, the sum of the torques on both sides must be equal. Torque is calculated by multiplying the force applied by the distance from the pivot point.
Given that the girl weighs 45 kg and is sitting 0.6 m away from the pivot point, the torque she applies is:
Torque(girl) = Weight(girl) x Distance(girl) = 45 kg x 0.6 m = 27 N·m
Let's assume that the boy sits at a distance of x meters from the pivot point. Since both sides must balance, we can set up the equation:
Torque(girl) = Torque(boy)
27 N·m = Weight(boy) x Distance(boy)
Since the weight of the boy is given as 60 kg, the equation becomes:
27 N·m = 60 kg x Distance(boy)
To find the distance the boy must sit, isolate Distance(boy):
Distance(boy) = 27 N·m / (60 kg) = 0.45 m
Therefore, the boy must sit 0.45 m away from the pivot point in order to balance the see-saw.
To balance a seesaw, the torques on either side of the pivot point must be equal. Torque is calculated by multiplying the force exerted on an object by the distance from the pivot point to the point where the force is applied.
In this problem, we have a 45 kg girl sitting at one end of the seesaw, 0.6 m away from the pivot point. Let's call this distance "D1." We also have a 60 kg boy sitting on the other side of the seesaw, and we need to determine the distance away from the pivot point where he should sit. Let's call this distance "D2."
The torque exerted by the girl is given by:
Torque_Girl = Force_Girl x Distance_Girl
Since the seesaw is balanced, the torques exerted by the girl and the boy must be equal:
Torque_Girl = Torque_Boy
The force exerted by each person can be calculated using their weight and considering that weight is equal to mass multiplied by the acceleration due to gravity (9.8 m/s^2):
Force_Girl = mass_Girl x g
Force_Boy = mass_Boy x g
Substituting these equations into the torque equation, we get:
Force_Girl x Distance_Girl = Force_Boy x Distance_Boy
Plugging in the given values:
(45 kg x g) x 0.6 m = (60 kg x g) x Distance_Boy
The acceleration due to gravity cancels out, leaving us with:
45 x 0.6 = 60 x Distance_Boy
To find the Distance_Boy, we can rearrange the equation:
Distance_Boy = (45 x 0.6) / 60
Calculating this expression:
Distance_Boy = 0.45 m
Therefore, the boy must sit 0.45 meters away from the pivot point in order to balance the seesaw.