The sum of two consecutive numbers 122.what is the number
The sum of two consecutive integers can't be an even number, because the one number is even and the other odd.
in this case:
a = first number
b = second number
b = a + 1
a + b = 122
a + a + 1 = 122
2 a + 1 = 122 Subtract 1 to both sides
2 a + 1 - 1 = 122 - 1
2 a = 121 Divide both sides by 2
a = 121 / 2 = 60.5
b = a + 1 = 61.5
Are you sure the sum is = 122?
Let's call the first number x.
The second consecutive number would be x + 1.
According to the problem, the sum of these two numbers is 122.
So, we can write the equation:
x + (x + 1) = 122
Simplifying the equation:
2x + 1 = 122
Subtracting 1 from both sides of the equation:
2x = 121
Dividing both sides of the equation by 2:
x = 121/2
Therefore, the first number is 60.5.
The second consecutive number would be:
x + 1 = 60.5 + 1 = 61.5.
So, the two consecutive numbers are 60.5 and 61.5.
To find the two consecutive numbers, we can use algebraic equations.
Let's assume that the smaller number is x. Since the numbers are consecutive, the next number would be x + 1.
According to the given information, the sum of these two numbers is 122, so we can write the equation:
x + (x + 1) = 122
Simplifying the equation, we get:
2x + 1 = 122
Now, let's solve for x:
2x = 122 - 1
2x = 121
x = 121 / 2
x = 60.5
Since we are dealing with consecutive numbers, x cannot be a decimal. Therefore, we can conclude that there are no two consecutive whole numbers whose sum is 122.