School is 2 miles from home along a straight road. The table shows your distance from home as you walk home at a constant rate.

Time(mins): 10-20-30
Distnce(mi)1.5-1-0.5

1)Is the relationship in the table
proportional?
2)Find your distance from school fro each time in the table
3)Write an equation representing the relationship between the distance from school and time walking.

**I hope the table makes sense, it's 10 mins for 1.5 miles, 20 mins for 1 mile, 30 mins for .5 mile.
THANK YOU!!

(1) no

(3) starting at (10,1.5), d decreases by .5 every 10 minutes
d = 1.5 - 0.5((t-10)/10)
= 3/2 - (t/10 - 1)/2
= 3/2 - t/20 + 1/2
= 2 - t/20
or, if you like decimals, d = 2.0 - 0.05t

lucy gurl calm down

why didnt you answer number 2

Thanks

1) To determine if the relationship in the table is proportional, we need to check if the ratio between distance and time remains constant. Let's calculate the ratios for the given data:

For 10 mins: Distance/Time = 1.5 miles / 10 mins = 0.15 miles per minute
For 20 mins: Distance/Time = 1 mile / 20 mins = 0.05 miles per minute
For 30 mins: Distance/Time = 0.5 miles / 30 mins = 0.0167 miles per minute

As we can see, the ratios are not the same. Therefore, the relationship in the table is not proportional.

2) If we want to find the distance from school for each time in the table, we can directly read it from the table you provided:

For 10 mins, the distance from school is 1.5 miles.
For 20 mins, the distance from school is 1 mile.
For 30 mins, the distance from school is 0.5 miles.

3) To write an equation representing the relationship between the distance from school and time walking, we can observe that the distance decreases linearly as the time increases.

Let's use the slope-intercept form of a linear equation, y = mx + b, where y represents the distance from school, x represents the time walking, m represents the slope, and b represents the y-intercept.

We can calculate the slope using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are any two points from the table.

Using (10 mins, 1.5 miles) and (30 mins, 0.5 miles):
m = (0.5 - 1.5) / (30 - 10) = -1 / 20 = -0.05

The negative sign indicates a decreasing relationship.

Now we can substitute one of the points and the calculated slope into the equation:

1.5 = (-0.05 * 10) + b
1.5 = -0.5 + b
b = 2

Therefore, the equation representing the relationship between the distance from school (y) and time walking (x) is:
y = -0.05x + 2

what does t mean

For the answer to part 2, (B) It is .5 / 1 / 1.5 / The problem states you are 2 miles from home so just subtract the dist from home on all of them

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