Graph y=2csc(x-π)
New period that I solve for 0<x-π<2π
π<x<3π
What is my quarter period?
I got that it was 3π/4 but when I add this to pi 4 times o reach 4π instead of 3π.
Please help.
you have a phase shift only. The period is unchanged at 2π.
To find the quarter period of the function y = 2csc(x - π), you need to determine the interval within which the graph of the function repeats itself.
First, let's find the period of the function. The period of the function y = csc(x) is 2π, which means the graph repeats itself every 2π units. However, in this case, the function is shifted by π units to the right, so the period becomes 2π units shifted to the right.
In order to find the desired quarter period within the interval 0 < x - π < 2π, we will divide the period by 4. So, the quarter period will be:
Quarter Period = (Period of shifted function)/4
= (2π)/(4)
= π/2
Therefore, the quarter period is π/2.
It seems like you might have confused the quarter period with the actual period of the function. When you added π/2 (the quarter period) to π four times, it reached 4π (the actual period). However, for the quarter period, you only need to add π/2 once.