When 22.3 mL of 1.00 M AgNO3 is mixed with 21.7 mL of 1.50 M NaCl, the temperature of the mixture rises for 21.6 degrees C to 29.7 degrees C. The mass of the aqueous mixture is 45.9 grams and its specific heat capacity is 3.94 J/grams degrees C
A very interesting post but I don't see a question.
so, I guess the question is "m of AgCl produced"???
I don't think so. The question probably is to determine delta H in kJ/mol for the reaction.
yes I need to find delta H. I calculated (45.9g)x (3.94J/g Celsius) x (8.1 Celsius), which came out to 1464.8526 Joules. How do I use this into solving for Delta H?
To solve this problem, we need to use the equation q = mcΔT, where q is the heat absorbed or released, m is the mass of the solution, c is the specific heat capacity of the solution, and ΔT is the change in temperature.
Here's how we can calculate the heat absorbed or released:
1. Determine the mass of the solution:
Given that the mass of the aqueous mixture is 45.9 grams.
2. Calculate the change in temperature (ΔT):
The temperature of the mixture rises from 21.6°C to 29.7°C. So, ΔT = 29.7°C - 21.6°C = 8.1°C.
3. Calculate the heat absorbed or released (q):
q = mcΔT
But since we don't know the total mass or specific heat capacity of the solution, we need to calculate it first.
- For AgNO3:
Given volume of 22.3 mL and molarity of 1.00 M.
First, calculate the moles of AgNO3:
Moles = volume (in L) * molarity = 22.3 mL * (1 L/1000 mL) * 1.00 M = 0.0223 moles
Then, calculate the mass of AgNO3 using its molar mass:
Molar mass of AgNO3 = 107.87 g/mol + 14.01 g/mol + (3 * 16.00 g/mol) = 169.87 g/mol
Mass = moles * molar mass = 0.0223 moles * 169.87 g/mol = 3.795 grams
- For NaCl:
Given volume of 21.7 mL and molarity of 1.50 M.
First, calculate the moles of NaCl:
Moles = volume (in L) * molarity = 21.7 mL * (1 L/1000 mL) * 1.50 M = 0.03255 moles
Then, calculate the mass of NaCl using its molar mass:
Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
Mass = moles * molar mass = 0.03255 moles * 58.44 g/mol = 1.9013 grams
- For the aqueous mixture:
Total mass = mass of AgNO3 + mass of NaCl = 3.795 grams + 1.9013 grams = 5.6963 grams
4. Now that we have the mass of the solution (m) and the change in temperature (ΔT), we can calculate the heat absorbed or released (q):
q = mcΔT
= 5.6963 grams * 3.94 J/g°C * 8.1°C
= 185.62 J
Therefore, the heat absorbed or released in this reaction is 185.62 Joules.