A backyard swimming pool holds 185 cubic yards (yd^3) of water. What is the mass of the water in pounds?

30" cylinders drum which 3 ' high completely filled with water what is the weight of the water in the drum

4995

To calculate the mass of the water in pounds, we need to know the density of water in pounds per cubic yard.

The density of water is approximately 62.4 pounds per cubic foot (lb/ft^3). Since 1 yard is equal to 3 feet, we can convert this to pounds per cubic yard by multiplying the density by the ratio of cubic feet to cubic yards.

1 cubic yard = 3 feet × 3 feet × 3 feet = 27 cubic feet

So, the density of water in pounds per cubic yard is:

62.4 lb/ft^3 × (1 yd^3 / 27 ft^3) = 2.315 lb/yd^3 (rounded to three decimal places)

Now, we can calculate the mass of the water in pounds by multiplying the volume of the pool in cubic yards by the density:

Mass (in pounds) = Volume (in cubic yards) × Density (in pounds per cubic yard)

Mass = 185 yd^3 × 2.315 lb/yd^3 = 428.775 pounds

Therefore, the mass of the water in the backyard swimming pool is approximately 428.775 pounds.

185 yd^3 x (3 ft/yd) x (3 ft/yd) x *3 ft/yd) = ? cubic feet.

Density H2O is 62.3 lbs/ft^3 @ 70 F.
mass = volume x density
mass in lbs = volume in ft^3 x density (lbs/ft^3)