If bus 1 and bus 2 leaves the station every 20 minutes and bus 2 leaves every 25 minutes...then what time will they leave the station at the same time again?
well,
20 = 4*5
25 = 5*5
So, what do you think?
after 200 minutes
But how does this work
this is so late but the answer is after 100 minutes / 1hr 40mins
To find the time when both buses will leave the station at the same time again, we need to determine the least common multiple (LCM) of the intervals between their respective departures.
The first bus leaves every 20 minutes, so its departure times can be represented by the sequence: 20, 40, 60, 80, ...
The second bus leaves every 25 minutes, so its departure times can be represented by the sequence: 25, 50, 75, 100, ...
To find the LCM of 20 and 25, we can list out the multiples of each number until we find a common multiple:
Multiples of 20: 20, 40, 60, 80, 100, ...
Multiples of 25: 25, 50, 75, 100, ...
From the lists, we find that the LCM of 20 and 25 is 100. Therefore, the buses will leave the station at the same time again in 100 minutes.
To determine the actual time when they will leave the station together, we need a reference point. Let's assume the first bus leaves the station at time 0. Then the second bus will leave the station at time 80, and they will meet again in 100 minutes, at time 180.
Therefore, they will leave the station at the same time again at time 180.