Win 1010” AM radio broadcasts at 1010KHz. Determine the wavelength of its signal, knowing that all radio waves travel at 3.00 X 10^8 m/s.

Question

Win 1010” AM radio broadcasts at 1010KHz. Determine the wavelength of its signal, knowing that all radio waves travel at 3.00 X 10^8 m/s.

f=1010kHz
v=3.00 X10^8 m/s
v=F X lambda
lambda= 2.9 X 10^5

For a particular type of wave in a particular medium why must f and lambda be inversely proportional.

Frequency deals with the number of waves per second, while wavelength deals with the distance from peak to peak. It would be inversely proportional because lambda deals with horizontal displacement and f deals with just the number of waves per time

Thank you for any help

f=1010kHz
v=3.00 X10^8 m/s
v=F X lambda
lambda= 2.9 X 10^5
Did you change kHz to Hz? If I divide by 1.010 x 10^6 Hz, I get 297 meters. Or did I make a mistake?

Answer 1

No, you did not make a mistake. The frequency given is indeed in kilohertz (kHz), which is equivalent to 1.010 x 10^6 Hz. By dividing the speed of light (v = 3.00 x 10^8 m/s) by the frequency (f = 1.010 x 10^6 Hz), you correctly calculated the wavelength (λ) to be approximately 297 meters. Therefore, the wavelength of Win 1010's radio signal is approximately 297 meters. Well done!