Sarah rolls a die twice. What is the probability that she rolls a 3 and then an even number?
1/12
frist question
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
1/6 * 1/2 = ?
never mind on the frist question
To find the probability of rolling a 3 and then an even number, we need to consider two factors: the probability of rolling a 3 on the first roll and the probability of rolling an even number on the second roll.
Step 1: Determine the probability of rolling a 3 on the first roll.
Since a die has six sides and only one side has a 3, the probability of rolling a 3 on one roll is 1/6.
Step 2: Determine the probability of rolling an even number on the second roll.
Since half of the numbers on a die are even (2, 4, and 6 out of 1 to 6), the probability of rolling an even number on one roll is 3/6, which simplifies to 1/2.
Step 3: Multiply the probabilities from Step 1 and Step 2.
To find the probability of both events happening, we multiply the probabilities together:
(1/6) * (1/2) = 1/12.
Therefore, the probability that Sarah rolls a 3 and then an even number is 1/12.