1/5(x+160)=2/3x-2
I'll assume you mean
(x+160)/5 = 2/(3x-2)
(x+160)(3x-2) = 10
3x^2+476x-330 = 0
Now you can use the quadratic formula.
If that's not what you meant, how about some parentheses to clarify the grouping?
(x+160)/5 = 2/(3x-2)
(x+160)(3x-2) = 10
3x^2+476x-330 = 0
Now you can use the quadratic formula.
If that's not what you meant, how about some parentheses to clarify the grouping?