How many moles of iron(iii) chloride could be made with an unlimited supply of iron atoms but only 1.81 X 10e23 chlorine atoms?

1.81E23 Cl atoms/6.02E23 = ? mols Cl atoms

You can make 1/3 of that number of FeCl3 moles.

To determine the number of moles of iron(III) chloride that can be made, we need to first determine the balanced chemical equation for the reaction of iron atoms with chlorine atoms to form iron(III) chloride.

The balanced chemical equation for this reaction is:

2 Fe + 3 Cl2 → 2 FeCl3

From the balanced equation, we can see that two moles of iron react with three moles of chlorine gas to produce two moles of iron(III) chloride.

Given that you have an unlimited supply of iron atoms but only 1.81 × 10^23 chlorine atoms, we need to calculate how many moles of chlorine atoms we have.

The number of moles can be calculated using Avogadro's number, which states that one mole of any substance contains 6.022 × 10^23 particles (atoms, molecules, etc).

Number of moles of chlorine atoms = (1.81 × 10^23) / (6.022 × 10^23) = 0.300 moldes

Since we have two moles of iron(III) chloride formed for every three moles of chlorine atoms, we can determine the maximum number of moles of iron(III) chloride that can be produced as follows:

0.300 moles of chlorine atoms × (2 moles of FeCl3 / 3 moles of Cl2) = 0.200 moles of FeCl3

Therefore, with an unlimited supply of iron atoms and 1.81 × 10^23 chlorine atoms, you can make 0.200 moles of iron(III) chloride.