For a crystal with formula BaCl2.xH2O, a student conducted a gravity experiment and found out that 2.44 gram of this crystal can lost mass 0.36 gram when heated to 150 degree. Suppose water is the only reason of weight loss, what is the x value here? (Molar mass of BaCl2 is 208 g/mole and H2O is 18 g/mole.

Question

For a crystal with formula BaCl2.xH2O, a student conducted a gravity experiment and found out that 2.44 gram of this crystal can lost mass 0.36 gram when heated to 150 degree. Suppose water is the only reason of weight loss, what is the x value here? (Molar mass of BaCl2 is 208 g/mole and H2O is 18 g/mole.

Answer 1

2.44 g = mass BaCl2 + xH2O

-0.36 g = mass H2O
----------
2.08 g = mass BaCl2

mols BaCl2 = 2.08/208 = 0.01
mols H2O = 0.36/18 = 0.02
BaCl2.2H2O

Answer 2

To determine the value of "x" in the formula BaCl2.xH2O, we need to find the amount of water lost when the crystal is heated.

First, let's calculate the molar mass of BaCl2 using the given information:
Molar mass of BaCl2 = 2*(Atomic mass of Ba) + Atomic mass of Cl
= 2*(137) + 35.5
= 271

Next, we'll calculate the molar mass of the water molecule (H2O):
Molar mass of H2O = 2*(Atomic mass of H) + Atomic mass of O
= 2*(1) + 16
= 18

Now, let's calculate the number of moles of BaCl2 in 2.44 grams:
Number of moles = mass / molar mass
= 2.44 / 271
≈ 0.009 moles

We know that the mass of water lost is 0.36 grams. To determine the number of moles of water lost, we can use its molar mass:
Number of moles of H2O = mass / molar mass
= 0.36 / 18
= 0.02 moles

Finally, we can determine the value of "x" by dividing the number of moles of water lost by the number of moles of BaCl2:
x = Moles of H2O / Moles of BaCl2
= 0.02 / 0.009
≈ 2.22

Therefore, the value of "x" in BaCl2.xH2O is approximately 2.22.

Answer 3

To determine the value of x in the formula BaCl2.xH2O, we first need to calculate the number of moles of water lost during the heating process.

Given:
- Mass of the crystal before heating = 2.44 grams
- Mass lost during heating = 0.36 grams
- Molar mass of BaCl2 = 208 g/mole
- Molar mass of H2O = 18 g/mole

First, we need to calculate the moles of BaCl2 in the crystal:
Moles of BaCl2 = Mass of BaCl2 / Molar mass of BaCl2
Moles of BaCl2 = 2.44 grams / 208 g/mole
Moles of BaCl2 = 0.0117 mole

Next, we calculate the moles of water lost during heating:
Moles of water lost = Mass of water lost / Molar mass of water
Moles of water lost = 0.36 grams / 18 g/mole
Moles of water lost = 0.02 mole

Since BaCl2 and H2O have a 1:1 stoichiometric ratio, the number of moles of water lost is equal to the value of x.

Therefore, the value of x is 0.02.