An object moving in a straight line at a constant velocity of 2m/s accelerates at 3m/s2 for 4s . what's the displacement of the object ?

Vo = 2 m/s.

t = 4 s.
a = 3 m/s^2.

d = Vo*t + 0.5a*t^2.

To find the displacement of the object, we can use the kinematic equation:

displacement = initial velocity * time + (1/2) * acceleration * time^2

Given:
Initial velocity (u) = 2 m/s
Acceleration (a) = 3 m/s^2
Time (t) = 4 s

Using the equation, we can calculate the displacement:

displacement = (2 m/s) * (4 s) + (1/2) * (3 m/s^2) * (4 s)^2
displacement = 8 m + (1/2) * 3 m/s^2 * 16 s^2
displacement = 8 m + 24 m
displacement = 32 m

Therefore, the displacement of the object is 32 meters.

To find the displacement of the object, we can use the formula:

displacement = initial velocity * time + (1/2) * acceleration * time^2

Let's break down the given information and calculate the displacement step by step:

Initial velocity (u) = 2 m/s
Acceleration (a) = 3 m/s^2
Time (t) = 4 s

First, we need to find the change in velocity during the 4 seconds of acceleration. Since the acceleration is constant, we can calculate the change in velocity using the equation:

change in velocity (Δv) = acceleration * time

Δv = 3 m/s^2 * 4 s = 12 m/s

Next, we can calculate the final velocity (v) after the 4 seconds of acceleration. Since the initial velocity is 2 m/s and there is a change in velocity of 12 m/s, the final velocity can be calculated as:

final velocity (v) = initial velocity + change in velocity

v = 2 m/s + 12 m/s = 14 m/s

Now, using the equation for displacement:

displacement = initial velocity * time + (1/2) * acceleration * time^2

displacement = 2 m/s * 4 s + (1/2) * 3 m/s^2 * (4 s)^2
displacement = 8 m + (1/2) * 3 m/s^2 * 16 s^2
displacement = 8 m + 24 m
displacement = 32 m

Therefore, the displacement of the object is 32 meters.