the perimeter of a rectangular athletic football field is 132 yards. the width is 12 yards less than half the length. what are the dimensions

P = 2L + 2W

132 = 2L + 2(0.5L - 12)

132 = 3L - 24

156 = 3L

52 = L

To find the dimensions of the rectangular athletic football field, we need to set up an equation based on the given information.

Let's assume the length of the football field is "L" yards.

Given that the width is 12 yards less than half the length, we can express it as: (L/2) - 12 yards.

The perimeter of a rectangle is calculated by adding the lengths of all its sides. For a rectangle, the formula is:

Perimeter = 2 * (length + width)

Substituting the values, we have:

132 = 2 * (L + (L/2) - 12)

Now we can simplify the equation and solve for L:

132 = 2 * (3L/2 - 12)

132 = 3L - 24

3L = 132 + 24

3L = 156

L = 156/3

L = 52

Now that we have the length, we can substitute it back into the expression for the width:

Width = (L/2) - 12
Width = (52/2) - 12
Width = 26 - 12
Width = 14

Therefore, the dimensions of the rectangular athletic football field are 52 yards (length) and 14 yards (width).