2t+8 is equal to or more than -4(t+1)
Can someone walk me through this please? Math really is my worst subject....
2t+8 >= -4t-1
add 4t+1 to each side
6t+9 >= 0
subtract 9 from each side
6t >= -9
divide each side by six
t >= -1.5
Oh....Okay I get it now, Thank you!
Of course! I can walk you through this math equation step by step. Let's start by simplifying both sides of the equation.
The given equation is 2t + 8 ≥ -4(t + 1).
Step 1: Distribute the -4 on the right side of the equation:
2t + 8 ≥ -4t - 4
Step 2: Combine like terms on both sides:
2t + 8 + 4t ≥ -4
This simplifies to:
6t + 8 ≥ -4
Step 3: Next, we want to isolate the variable "t" by moving the constant term (in this case, 8) to the other side of the equation. To do that, we subtract 8 from both sides:
6t + 8 - 8 ≥ -4 - 8
This simplifies to:
6t ≥ -12
Step 4: Finally, to solve for "t," we divide both sides of the equation by 6:
(6t)/6 ≥ (-12)/6
This gives us:
t ≥ -2
So, the solution to the equation 2t + 8 ≥ -4(t + 1) is t ≥ -2.