upthrust is equol apparent loss of weight is 200n fine the volume

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To find the volume in this situation, we need to understand what upthrust is and how it is related to the apparent loss of weight.

Upthrust, also known as buoyant force, is the force exerted by a fluid (liquid or gas) on an object submerged or partially submerged in it. It acts in the upward direction and is equal to the weight of the fluid displaced by the object.

Apparent loss of weight refers to the decrease in apparent weight experienced by an object when submerged in a fluid. It occurs because the upthrust acts in the opposite direction to gravity, partially counteracting it and reducing the overall weight of the object.

In your question, the given value for the apparent loss of weight is 200N. To find the volume related to this, we can use Archimedes' principle, which states that the upthrust experienced by an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

1. Determine the weight of the fluid displaced:
Since the upthrust is equal to the apparent loss of weight, the weight of the fluid displaced is also 200N.

2. Use the formula for the weight of a fluid:
weight = density x volume x gravity

We know the weight of the fluid (200N) and the density of the fluid is usually given or determined based on the context of the problem.

Let's assume the density of the fluid (ρ) is known in kg/m^3.

Therefore, we can rearrange the formula to solve for volume:

volume = weight / (density x gravity)

Substitute the given values into the formula and calculate the volume.